0=16t^2+4-t+20

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Solution for 0=16t^2+4-t+20 equation: 



0=16t^2+4-t+20

We move all terms to the left:

0-(16t^2+4-t+20)=0

We add all the numbers together, and all the variables

-(16t^2+4-t+20)=0

We get rid of parentheses

-16t^2+t-4-20=0

We add all the numbers together, and all the variables

-16t^2+t-24=0

a = -16; b = 1; c = -24;
Δ = b2-4ac
Δ = 12-4·(-16)·(-24)
Δ = -1535
Delta is less than zero, so there is no solution for the equation

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